Get the next day of a date
This is an open discussion with 4 replies, filed under XSLT.
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- michael-e
- 28 Mar 12, 8:20 pm
- Comment #2
Wouldn't this the be much simpler using EXSLT's date functions? (And leap years would also work!)
This stylesheet can give you a start:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:date="http://exslt.org/dates-and-times"
extension-element-prefixes="date">
<xsl:output method="xml"
omit-xml-declaration="yes"
encoding="UTF-8"
indent="yes" />
<xsl:template match="/">
<xsl:param name="date" select="'2012-02-28'"/>
<data>
<date>
<xsl:value-of select="$date"/>
</date>
<one-day-after-date>
<xsl:value-of select="date:add($date, 'P1D')"/>
</one-day-after-date>
<two-days-after-date>
<xsl:value-of select="date:add($date, 'P2D')"/>
</two-days-after-date>
</data>
</xsl:template>
</xsl:stylesheet>
The output will be:
<data> <date>2012-02-28</date> <one-day-after-date>2012-02-29</one-day-after-date> <two-days-after-date>2012-03-01</two-days-after-date> </data>
[EDIT]: Simplified stylesheet.
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- dbraband
- 28 Mar 12, 11:10 pm
- Comment #3
I see it as a challenge. Here is the latest version with leap year.
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- michael-e
- 29 Mar 12, 12:12 am
- Comment #4
:-)
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- animaux
- 02 Jul 19, 7:28 pm
- Comment #5
I was wondereing why it didn’t work in my case just now. I borked up the namespace … thanks to this page I found the error :) thanks Michael!
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